To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
Answer:
16. Angle C is approximately 13.0 degrees.
17. The length of segment BC is approximately 45.0.
18. Angle B is approximately 26.0 degrees.
15. The length of segment DF "e" is approximately 12.9.
Step-by-step explanation:
<h3>16</h3>
By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.
For triangle ABC:
- ,
- The opposite side of angle A ,
- The angle C is to be found, and
- The length of the side opposite to angle C .
.
.
.
Note that the inverse sine function here is also known as arcsin.
<h3>17</h3>
By the law of cosine,
,
where
- , , and are the lengths of sides of triangle ABC, and
- is the cosine of angle C.
For triangle ABC:
- ,
- ,
- The length of (segment BC) is to be found, and
- The cosine of angle A is .
Therefore, replace C in the equation with A, and the law of cosine will become:
.
.
<h3>18</h3>
For triangle ABC:
- ,
- ,
- , and
- Angle B is to be found.
Start by finding the cosine of angle B. Apply the law of cosine.
.
.
.
<h3>15</h3>
For triangle DEF:
- The length of segment DF is to be found,
- The length of segment EF is 9,
- The sine of angle E is , and
- The sine of angle D is .
Apply the law of sine:
.
Answer:
- Let p be the population at t be the number of years since 2011. Then,
- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then,
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get
Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get
Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
Answer:
opposite sides with equal length
hope it helps
Answer:
-5
Step-by-step explanation:
7−12
=7−12
=7+−12
=−5