A = {0, 1, 2, 3}
C = {0, a, 2, b}
A ∩ C = {0, 2} → E)
A set of the same elements from the set A and the set C.
If R is between Q and S then QR+RS=QS
given
QR=x+4
RS=3x-1
and QS=27
x+4+3x-1=27
combine like terms
4x+3=27
minus 3 both sides
4x=24
divide both sides by 4
x=6
sub back
QR=x+4
QR=6+4
QR=10
RS=3x-1
RS=3(6)-1
RS=18-1
RS=17
x=6
QR=10
RS=17
Answer:
h > 24
Step-by-step explanation:
h/3 > 8
so basially you move the number three from the left side to the right side
so from division to multiplication
h > 8 x 3
h > 24
Solved !
Hope it helped ! Have a nice day !
The final answer is 34.0
See the attached image to see how I got that answer.