The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
140 minutes
Step-by-step explanation:
After 28 mins you've gone 4 miles, assuming this rate is constant and you dont slow down or speed up, in order to get to 20 miles you will have run 5x as much (20/4 = 5), thus 5x the amount of time (28x5).
20/4 = 5
5x28 = 140
Answer: d) (3, 3)
<u>Step-by-step explanation:</u>
Inverse is when you swap the x's and y's.
Let's look at the points and find their inverse:
f(x) f⁻¹(x)
(0, -2) --> (-2, 0)
(1, -1) --> (-1, 1)
(2, 0) --> (0, 2)
(3, 3) --> (3, 3) f(x) = f⁻¹(x) so this is where they intersect!
Answer:
im in middle school and im trying to figure this out as well
Step-by-step explanation:
sorry if i get it i will tell you