A 0.358 kg particle slides around a horizontal track. The track has a smooth, vertical outer wall forming a circle with a radius
1 answer:
Answer:
The energy loss due to friction in one revolution is 4.92 J.
Explanation:
Given that,
Mass of particle = 0.358 kg
Radius = 1.66 m
Initial speed =8.19 m/s
Final speed = 6.29 m/s
We need to calculate the kinetic energy
Using formula of kinetic energy
Put the value into the formula
Hence, The energy loss due to friction in one revolution is 4.92 J.
You might be interested in
Answer:
Distance: 21 yd, displacement: 15 yd, gain in the play: 12 yd
Explanation:
The distance travelled by Sam is just the sum of the length of each part of Sam's motion, regardless of the direction. Initially, Sam run from the 3 yd line to the 15 yd line, so (15-3)=12 yd. Then, he run also 9 yd to the right. Therefore, the total distance is
d = 12 + 9 = 21 yd
The displacement instead is a vector connecting the starting point with the final point of the motion. Sam run first 12 yd straight ahead and then 9 yd to the right; these two motions are perpendicular to each other, so we can find the displacement simply by using Pythagorean's theorem:
Finally, the yards gained by Sam in the play are simply given by the distance covered along the forward-backward direction only. Since Sam only run from the 3 yd line to the 15 yd line along this direction, then the gain in this play was
d = 15 - 3 = 12 yd
Answer:
Explanation:
We need to assume that the density of the concrete is about 2350 Kg/m^3. And using the dimensions of the highway we can calculate the volume of the highway.