Answer:
im sorry, i cant see the screen very well...
Step-by-step explanation:
To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:
Step-by-step explanation:
y 1 = StartFraction log x Over log 0.5 EndFraction, y 2 = StartFraction log 2 Over log 3 EndFraction + x
Answer:
1. 1/4
2. 5/6
3. 87/40
4. 2/11
5. 49/54
6. 3/8
7. 9/2
8. 5
9. 31/9
10. 25/12
x=3 and y=2 because 6+6 = 12 and 2 times 3 is 6 :)