Answer:
Explanation:
To calculate the heat of reaction we need to determine:
- The heat produced
- The moles of Zn that reacted
<u>Moles of zinc (Zn)</u>
It says that the 0.103 g reacted completely, knowing that the Zn molecular weight is 65.4 g/mol:
<u>Heat released by the reaction</u>
The solution goes from 22.5 °C to 23.7°C:
<u>Heat of reaction</u>
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6 protons, 6 neutrons, and 5 electrons
Molar mass Li2O = 7.0 x 2 + 16 => 30 g/mol
1 mole Li2O ---------- 30 g
( moles Li2O ) -------- 45.0 g
moles Li2O = 45.0 x 1 / 30
moles Li2O = 45.0 / 30
= 1.50 moles of Li2O
hope this helps!