1/5 is greater because it equals 0.2
0.2 has an imaginary 0 at the end, to make it 0.20
.20 > 0.15
Therefore, 1/5 is greater than 0.15
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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Answer:false
Step-by-step explanation:no constant rate of change in y and x values
Answer:
2sin^2(3x)
Step-by-step explanation:
NAMASTE :)
0.00000000005
= 5 ×
Count the Digits after decimal.
We use minus (-) in power as the digit is in left side of decimal
If they are in right side then we use (+) plus sign in power.
