Jess had three more nickels than dimes for a total of $1.50 how many of each coin did he
1 answer:
n = d + 3
5n + 10d = 150 cents
Substitute to solve for "d":
5(d+3)+10d = 150
15d + 15 = 150
15d = 135
d = 9 dimes
n = d+3 = 9+3 = 12 nickels
So 12 nickels!!
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