2 years ago

I need help with these 2 questions.

Mathematics

1 answer:

Usimov [2.4K]2 years ago

3 0

The first one is 32m^15n^10
The second one is:
(h^12/h^4)^5
(h^6/h)^5
h^30/h^5
h^25/h

Hope this helps :)

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Step-by-step explanation:

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A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun

bija089 [108]

Answer:

$3x^{3}+15x^{2}+x+5$

Step-by-step explanation:

We are told that the area of the bag can be represented by the function $f(x)=3x^{2} +1$ and as the bag is raised up its height can be represented by the function $g(x)=x +5$ .

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

$\text{Volume of collapsible bag}=f(x)*g(x)$

$\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)$

After using distributive property we will get,

$\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)$

$\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5$

Therefore, the collapsible bag can hold $3x^{3}+15x^{2}+x+5$ grain.

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2 years ago