We can convert that into a fraction of 100 for the percentage.
4/20= 20/100
(multiply both by 5)
So, the basketball player makes 20% of the throws.
I hope this helps!
~kaikers
Answer:
a(4) = 15/4
Step-by-step explanation:
Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.
Thus, the geometric sequence formula specific to this case is
a(n) = 30(1/:2)^(n-1).
What is the fourth term? Let n = 4,
a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or a(4) = 30(1/8) = 30/8, or, in reduced form,
a(4) = 15/4.
Answer:
12
Step-by-step explanation:
A 2 - sided counter ; (red, yellow)
A spinner (1,2,3,4,5,6)
Number of trials = 80
P(red and number > 3) :
P(red) = 1/2 ;
P(number >3) : numbers greater Than 3 = (4, 5, 6)
Hence, P(number <3) = 3 /6 = 1/2
Theoretical probability = 1/2 *1/2 = 1/4
Expected number of outcomes :
1/4 * number of trials
1/4 * 80 = 20
Experimental outcome :
Relative frequency = number of outcomes / number of trials
Relative frequency = 2/5
Hence,
2/5 = number of outcomes / 80
Cross multiply :
160 = number of outcomes * 5
Number of outcomes = 160 /5 = 32
Actual outcomes = 32
Difference between actual and expected :
32 - 20 = 12
Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.