The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.
Calculation,
Given data,
Mass of the ice = 10 g
Temperature of ice = 0. 0°C
- The ice at 0. 0°C is to be converted into water at 0. 0°C
Heat required at this stage = mas of the ice ×latent heat of fusion of ice
Heat required at this stage = 10 g×80 = 800 cal
- The temperature of the water is to be increased from 0. 0°C to 100. 0°C
Heat required for this = mass of the ice×rise in temperature×specific heat of water
Heat required for this = 10 g×100× 1 = 1000 cal
- This water at 100. 0°C is to be converted into vapor.
Heat required for this = Mass of water× latent heat
Heat required for this = 10g ×536 =5360 cal
Total energy or heat required = sum of all heat = 800 +1000+ 5360 = 7160 cal
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Answer:
603 mL
Explanation:
A milliliter is a unit of volume equal to 1/1000th of a liter. It is the same as a cubic centimeter.
Answer: The compound is called copper (II) bromide or cupric bromide
Explanation:
<span>Answer:
if it was planar the center of the negative forces and the center of the positive forces would be at the same place, meaning no di-poles would form so it wouldnt be polar. as it is polar it therefore cannot be planar.
the neagative center(pole) is above the the positive one due to the pair of unbonded electrons.</span>
Answer:
I believe it would be c
Explanation:
the cold an or warm air has no effect the plant must be on it original source
