Answer:
Average velocity = 18 m/s
Explanation:
Given the following data;
Initial velocity = 10m/s
Acceleration = 2m/s²
Time = 4 seconds
To find the average velocity, we would use the first equation of motion;
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
V = u + at
V = 10 + 2*4
V = 10 + 8
V = 18 m/s
Answer:
Acceleration = 2.35 m/
Speed = 8.67 m/s
Explanation:
The coefficient of friction , u =0.3
The angle of incline = 30°
The two forces acting on block are weight and friction.
weight along the incline = mg cos60° = = 0.5 mg
Friction along incline = umg cos30° = mg
Friction along incline = 0.26 mg
Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg
Acceleration = = 0.24 g = 2.35 m/
The height of incline = 8 m
Length of the inclined edge = 16 m
v= 8.67 m/s
From the solution that I have done, the wavelength in the question that we have is 31.88 cm
<h3>How to solve for the wavelength</h3>
The frequency in the question is given as 40/30 = 1.33 hz
Next we have to solve for V
= 425/10
= 42.5 cm/s
v = frequency * wavelength
we have to put in the values in the formula. This would be
42.5 = 1.33 x wavelength
we have to divide through by 1.33 to get the wavelength. This would be
42.5/1.333 = wavelength
31.88 cm = wavelength
Hence we can say that the wavelength in the question that we have here is 31.88 cm
Read more on wavelength here:
brainly.com/question/10728818
#SPJ4
Solution:
We have,
Power [P] = 25000 Watt
Mass [m] = 6000 kg
Height [h] = 20 metres
Time [t] = ?
Now,
P = W/t = F x d/t = mxgx h/t
Or, 25000 = 6000 x 10 x 20/25000 [.......g = 10
m/s^2]
Or, t = 6000 x 10 x 20/25000
Or, t = 1200/25
Therefore, t = 48 second
Hence, the required time for the crane to lift the load is 48 seconds.
Answer:
1.62 atm
Explanation:
We can solve the problem by using the ideal gas equation:
where:
p = ? is the pressure of the gas in the tire
V = 8.5 L is the volume of the tire
n = 0.55 mol is the number of moles of the gas
R = 0.0821 atm L / K mol is the gas constant
T = 305 K is the temperature of the gas
By re-arranging the equation and substituting the numbers in, we find: