Answer: 9 pieces of ribbon
Explanation: 4.5 / 0.5 = 9
Answer:
dy/dx = 2x+1/x(x+1)
Step-by-step explanation:
y = In x(x+1)
Let u = x(x+1) = x^2 + x
du/dx = 2x + 1
y = In u
dy/du = 1/u
dy/dx = dy/du × du/dx = 1/u × 2x+1 = 2x+1/u = 2x+1/x(x+1)
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
Answer:
4) 6 students
5) 7 fewer students
6) No, you can not tell from the frequency table how many students ran a mile in exactly 12 minutes.
Step-by-step explanation:
4) you’d look at the row from 8:00-8:59.
5) Add the first two rows together (6+2=8), then subtract that by the sum of the last two rows (9+6=15), which is 7
6) There’s no pattern in the frequency table, and the data points would be plotted differently since it’d be from a range of times, not one set time.
Hope this helped, sorry if I’m wrong on #6 ;)
So I'm not totally sure but I got -15.32
So sorry if it's wrong!!
