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2 years ago

What is the solution to the equation 6x+ 2 - 9x-1? O X=-3 O X=-1 O X=1 O X-3

Mathematics

1 answer:

Nataly [62]2 years ago

3 0

Answer:

c isyour answer

Step-by-step explanation:

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What missing angle of the figure

aniked [119]

Answer:

138

Step-by-step explanation:

152+125=277

277-135=142

around 138

4 0

2 years ago

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Vika [28.1K]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Read 2 more answers

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

2 years ago

What is the area of a circle is the radius is 8

Shalnov [3]

When the radius is 8, the area would be 201.06

Area of circle = pi x radius² (pi x 8²)

8 0

2 years ago

Read 2 more answers

5/3 raise to minus 5 into 5/3 raise to minus 11 is equal to 5/3 raise to x

Soloha48 [4]

Answer:

x = -2

Step-by-step explanation:

x^a × x^b = x^(a+b)

Similarly,

(5/3)^(-5) × (5/3)^(-11) = (5/3)^(-5-11)

= (5/3)^(-16)

-16 = 8x

x = -2

7 0

2 years ago