Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
Sinx =8/40
in order to solve this you would have to use the inverse which would be Sin^-1(8/40) giving you 11.5
Attached the solution and work.
Answer:
The difference is 3 papers per hour
Step-by-step explanation:
First, you make turn the 10 minutes to 60 minutes by multiplied by 6 and the same to three and you would get 18 paper per hour. Next, you simplify the 8 minute rate to 1 paper in 4 minutes then multiply the 4 by 15 = 60 minutes then the same to the 1 equal to 15 paper per hour. Finally, you subtract 18 - 15 = 3 paper.
Answer:
x = 3/2
Step-by-step explanation:
2(x + 5) = 6x + 4
Open bracket first
2 × x + 2×5 = 6x + 4
2x + 10 = 6x + 4
Rewrite equation
6x + 4 = 2x + 10
Subtract 2x from both sides
6x - 2x + 4 = 2x - 2x + 10
4x + 4 = 10
Subtract 4 from both sides
4x + 4 - 4 = 10 - 4
4x = 6
Divide both sides by 4
4x/4 = 6/4
x = 6/4
Divide both denominator and numerator by 2
x = (6/4) ÷ 2
x = 3/2
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