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3 years ago

8

An ASB Robusta 300 TS sump pump can remove water from Martha's flooded basement in 70 min .The 1 Little Giant 1-A sump pump can

complete the same job in in 30 min. How long would it take the two pumps together to pump out the basement?

1 answer:

aleksandrvk [35]3 years ago

5 0

21 minutes. hope this helps.

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Please help me ASAP!!!!!!!!!!!!!!

earnstyle [38]

Answer:

7 Celsius

Step-by-step explanation:

Initial temperature at 12pm is 1 Celsius.

Rises by 6 (add by 6).

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2 years ago

A zookeeper feeds three bales of hay each to 4 elephants, 6 bales of hay to each of 10 pens of reindeer, 2 bales of hay to each

snow_lady [41]

Answer:

$105

Step-by-step explanation:

3x5=15

6x5= 30

2x5=10

4x5=20

6x5=30

15+30+10+20+30

=$105

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2 years ago

Agnes has 23 collectible stones, all of

Svetllana [295]

Answer:

The answer is she sold 20 labradorite crytals and 3 galena crystals.

Step-by-step explanation:

First you times 20 x 20 and get 400 and then times 13 x 3 and get 39 and 400 plus 39 equals $439.

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2 years ago

Please need help on this having a hard time with both of these

Arlecino [84]

Question 1 - the first choice is right
Question 2- the first choice also

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2 years ago

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power = 1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

2 years ago