We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
Here is the interest equation: I=prt
Where I is interest, p is principal, r is rate and t is time(in years).
Substitute with known values.
I= prt
I= 10000(.05)(1 and 1 over 4)
I= 625
Answer: $625 for 15 months.
Step-by-step explanation:
Taisha is losing money. Exactly how much can be found in this equation.
12 months in a year so that's our coefficient.
292.36(12) - 320.67(12)=−339.72
(pay per month) (school fee per month)
She is 339.72 dollars in debt.
