Answer:
93% probability of a student taking a calculus class or a statistics class
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a student takes a calculus class.
B is the probability that a student takes a statistics class.
We have that:
In which a is the probability that a student takes calculus but not statistics and is the probability that a student takes both these classes.
By the same logic, we have that:
The probability of taking a calculus class and a statistics class is 0.07
This means that
The probability of taking a statistics class is 0.90
This means that . So
The probability of a student taking a calculus class is 0.10
This means that
What is the probability of a student taking a calculus class or a statistics class
93% probability of a student taking a calculus class or a statistics class
Answer:
m - 11 = 44
Step-by-step explanation:
Breaking the phrase down...
"The difference of Malik's height and 11" - this indicates subtraction.
m - 11
"is 44" - this indicates that the value of the diffrence would be '44'.
'= 44'
The equation should be:
m - 11 = 44
Hope this helps.
Answer:
well, x = 5
Step-by-step explanation:
here,
EB Is parallel to DC , so
Angle AEB = Angle ADE
( because they are corresponding angle pair )
Angle ABE = Angle ACD
( because they are corresponding angle pair )
triangle ADC Is similar to triangle AEB
(By AA similarity criteria )
hence AE / ED = AB / BC ( by CPCT )
so 24/10 = 12/x
=》 24/12= 10/x
=》 x = 5
okay i hope u got it
Answer:
The fourth one: Gavin has one and thirteen fourteenths buckets of water. Daven has one and three fourteenths buckets of water. Together they have three and two fourteenths buckets of water.
Step-by-step explanation:
Gavin = 1 13/14
Daven = 1 3/14
1 13/14 + 1 3/14 = 2 16/14
2 16/14 = 3 2/14 = three and two fourteenths