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2 years ago

Ground-based radio telescopes can collect data from distant objects in space

2 answers:

6 0

Ground-based radio telescopes can collect data from distant objects in space during the day or night and in MANY different weather conditions.

BUT ...

-- of course, they have to avoid pointing at the Sun, since the Sun is a loud, humongous source of radio signals !

-- of course, they have to shut down during lightning storms and most rain, because lightning is a loud, humongous source of radio signals, and rain can generate radio static noise. Rain can also create puddles and unsymmetric wetting inside the radio "dish" antenna, which really messes up the gain and directional pattern of the antenna.

Arada [10]2 years ago

4 0

Answer is A. Because the telescope are use in night

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1. When an object is at rest, not moving, and is crashed into by another

wlad13 [49]

Answer:

both experience forces or at least a force

Explanation:

it would go in the direction the other object

(second object, the one that crashed) was going

si if going right then right if left then left

plus or minus

4 0

2 years ago

A raindrop of radius r falls from a certain height h above the ground. The work done by

lisabon 2012 [21]

Answer:

fhc

Explanation:

chchfufuufufyfydyedhxhfud wyruficjc

5 0

2 years ago

It is known that heat is added to a gas in sealed container. The container is fitted with a moveable piston.

jasenka [17]

Answer:

d. Not enough information is given to answer this question.

Explanation:

From first law of thermodynamics

Q= W + ΔU

Q=Heat ,W= Work , ΔU=Change in internal energy

If work done by the gas :

It means that W and Q both are positive

Q- W = ΔU

Ii Q > W ,then temperature of the gas will increase.

If Q< W ,Then temperature of the gas will decreases.

If work done on the gas:

Q positive but W will be negative

Q- W = ΔU

Q= W or Q>W or Q< W ,then temperature of the gas will increase.

There are three cases because they did not give any information about the work.That is why option d is correct.

3 0

2 years ago

A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo

Rasek [7]

Answer:

$t=12.25\ seconds$

Explanation:

<u>Diagonal Launch </u>

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

$x=v_ocos\theta t$

$\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}$

Where vo is the magnitude of the initial velocity, $\theta$ is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

$\displaystyle t=\frac{v_osin\theta}{g}$

There are two times where the value of y is $y_o$ when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making $y=y_o$

$\displaystyle y_o=y_o+v_osin\theta\ t-\frac{gt^2}{2}$

Removing $y_o$ and dividing by t (t different of zero)

$\displaystyle 0=v_osin\theta-\frac{gt}{2}$

Then we find the total flight as

$\displaystyle t=\frac{2v_osin\theta}{g}$

We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is

$\boxed{t=24.5/2=12.25\ seconds}$

4 0

2 years ago

Which statement is correct? (2 points)

Lemur [1.5K]

Answer:

When a neutral atom looses an electron to another neutral atom, two charged atoms are created.

Explanation:

On the off chance that one of the two unbiased particle looses an electron, it turns out to be emphatically (charge: +1), in light of the fact that the electron conveys a charge of - 1. Thus, the other atom which acknowledges the electron turns out to be adversely charged (charge: - 1). And in the end, we will have two charged atoms.

7 0

2 years ago