Answer:
Step-by-step explanation:
integral(x/(1+x^2)^2)dx
=(1/2)integral(2x/(1+x^2)^2)dx
=(1/2)[-1/(1+x^2)] +c
The explicit formula for calculating the sum is
The sum of the nth term of a sequence is expressed as;
a is the first term
d is the common difference
n is the number of terms
For the sequence 0 + 1 + 2 + 3 +...
Similarly for the sequence:
1 + 2+ 3 + 4+...
Taking the product of the sum to get the explicit formula for calculating the sum
Learn more here: brainly.com/question/24547297
3/4 + 2/3 = 17/12
7/8 - 2/3 = 5/24
3/5 x 1/3 = 1/5
4/7 x 2/3 = 8/21
I believe the answer is b