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2 years ago

Helllllllllppppp plllllsssss

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

8 0

Answer: It’s B

Because I took the quiz and got it right

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Help! What’s the y intercept of the linear equation 7+y=4.3x

Rasek [7]

Answer:

(0,-7)

Step-by-step explanation:

the y-intercept is found when the x-value is equal to 0. In this case, we are finding a coordinate pair. First, plug in 0 for x.

7+y=4.3(0)

simplify

7+y=0

subtract 7 from both sides

y=-7

Make it an ordered pair,

(0,-7)

8 0

2 years ago

What is required of a proportional relationship that is not required of a general linear relationship?

Lana71 [14]

The proportional relationship should require they y-intercept and is then 0 and the linear relationship should be in a straight line to be a linear! Hope this helps!

8 0

2 years ago

Hey guys! Sorry to bother but I need help with these. 5th grade math, will give brainliest! (If you see multiple questions by me

-Dominant- [34]

Answer:

Question 3: 1/15 Question 4: 50

Step-by-step explanation:

Just divide the fractions by the numbers.

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1 year ago

Please help me I really need help

elixir [45]

Answer:

Step-by-step explanation:

Lowest Common Multiple= 56

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2 years ago

Read 2 more answers

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

2 years ago