A+30 = 60
a = 30
a + 2b = 60
30+2b = 60
2b = 30
b = 15
5b - 5c = 60
5(15) - 5c = 60
5c = 15
c = 3
10c + d = 60
10(3) + d = 60
30 + d = 60
d = 30
2d + 6e = 180 - 60
2(30) + 6e = 120
6e = 60
e = 10
4f + 4e = 120
4f + 4(10) = 120
4f = 80
f = 20
Answer:
Car 1 : 40 miles per gallon
Car 2: 25 miles per gallon
Step-by-step explanation:
family has two cars. During one particular week, the first car consumed 15 gallons of gas. The second car consumed 25 gallons of gas. The two cars Drove a combined total of 1475 miles and the sum of their fuel efficiency was 65 miles per gallon. What were the fuel efficiency of each of the cars that week
Given that :
Fuel efficiency , car 1 = x
Fuel efficiency , car 2 = y
x + y = 65 - - (1)
15x + 35y = 1475 - - - (2)
x = 65 - y
15(65-y) + 35y
975 - 15y + 35y = 1475
20y = 14875 - 975
20y = 500
y = 25
Put y = 25 in (1)
x + y = 65
x + 25 = 65
x = 65 - 25
x = 40
Data:
r (radius) = 3.5 in
h (height) = 8 in
Adopt:
V (volume) = ?
Ink cost per cubic inch = $0.05/in³
Total cost: ?
<span>Calculate the volume of the paint bucket (its formed being cylindrical), we have:
</span>
<span>What was the total cost of the paint?
</span>price($)___measure(in³)
0.05 ---------- 1
y -------------- 307.72
It is made the rule of three: (<span>directly proportional)
</span>
multiply cross
Answer:
<span>
the total cost of the paint is $15</span>
Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2
Using simple interest, we have that:
A) The interest due after 8 months is $11,272.33.
B) The total value of the investment will be of $189,986.24.
The amount of interest earning using <em>simple interest</em>, after <u>t years</u>, with an <u>yearly interest rate of i</u> and an <u>initial investment of P</u> is given by:
In this problem:
- Deposit of $178,000, hence .
- Interest rate of 9.5% per year, hence .
- 8 months, the time is in years, hence
Item a:
The interest due after 8 months is $11,272.33.
Item b:
For the second interest, we consider , hence:
The total value will be composed by:
- The initial deposit of $178,000.
- The first interest of $11,272.33.
- The second interest of $713,91.
Hence, it will be:
The total value of the investment will be of $189,986.24.
A similar problem is given at brainly.com/question/13176347