Asked and answered elsewhere.
brainly.com/question/10192511Knowing that 1+2i is a root, you also know that 1-2i is a root, so one quadratic factor is
(x -1)² -(2i)² = x^2 -2x +5
Long division of the given polynomial by this quadratic gives a quotient of
x² +9
which has roots ±3i.
Then all
the roots are {-3i, 3i, 1-2i, 1+2i}.
No.
Since w = 8, you must replace the variable with the number associated to it.
So, it would be 5 + 8 = 58
5 + 8 is not equal to 58, it is equal to 13.
If you wanted to find out what w was, simply subtract 5 on both sides.
w = 58 - 5
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
To put this into slope-intercept form, you need to isolate/get the variable "y" by itself in the equation:
8x - 6y = 6 Subtract 8x on both sides
8x - 8x - 6y = 6 - 8x
-6y = -8x + 6 Divide -6 on both sides to get "y" by itself