Answer: The company should produce 7 skateboards and 16 rollerskates in order to maximize profit.
Step-by-step explanation: Let the skateboards be represented by s and the rollerskates be represented by r. The available amount of labour is 30 units, and to produce a skateboard requires 2 units of labor while to produce a rollerskate requires 1 unit. This can be expressed as follows;
2s + r = 30 ------(1)
Also there are 40 units of materials available, and to produce a skateboard requires 1 unit while a rollerskate requires 2 units. This too can be expressed as follows;
s + 2r = 40 ------(2)
With the pair of simultaneous equations we can now solve for both variables by using the substitution method as follows;
In equation (1), let r = 30 - 2s
Substitute for r into equation (2)
s + 2(30 - 2s) = 40
s + 60 - 4s = 40
Collect like terms,
s - 4s = 40 - 60
-3s = -20
Divide both sides of the equation by -3
s = 6.67
(Rounded up to the nearest whole number, s = 7)
Substitute for the value of s into equation (1)
2s + r = 30
2(7) + r = 30
14 + r = 30
Subtract 14 from both sides of the equation
r = 16
Therefore in order to maximize profit, the company should produce 7 skateboards and 16 rollerskates.
Answer:
The answer is D
Step-by-step explanation:
I did it on edg
The answer is: a = 16
Steps:
First exclude any restricted values of y.
6/y = 9/24 , y is not equal 0
Simplify the right side of the equation using 3.
6y = 3/8
Cross multiply.
6 x 8 = 3
3 x y = 3y
So, 6 x 8 = 3y
Or, 48 = 3y
Switch the sides of the equation.
3y = 48
Divide both sides by 3.
3y/3 = y
48/3 = 16
Now you have your answer, y = 16
