<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
<u>Explanation:</u>
Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized 
electrons are calculated by using the equation:
where,
n = 0 or any whole number
- Calculating the value of electrons for n = 0
Putting values in above equation, we get:
- Calculating the value of electrons for n = 1
Putting values in above equation, we get:
- Calculating the value of electrons for n = 2
Putting values in above equation, we get:
Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
Answer:
A. 1:3
Explanation:
If we look at the ions shown in the image attached to the question, we will notice that we have aluminum (Al^3+), a trivalent ion combining with the iodide ion (I^-).
Aluminum can easily give out its three outermost electrons to three atoms of iodine. If aluminum gives out its three electrons, it achieves the stable octet structure. Iodine atoms have seven electrons in their outermost shell. They only need one more electrons to complete their octet. This one electron can be gotten by the combination of three iodine atoms with one atom of aluminum. One electron each is transferred from the aluminum atom to each iodine atom to form AlI3 with a ratio of 1:3.
No. Magnesium, and Bromine are a chemical compound when put together.
Neither Bromine, nor Magnesium react with any sort of water.
The answer is d. extrusive.
The other term for it is <em>igneous rock</em>. Igneous rock is made in lava, and another term for igneous rock is extrusive rock.
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Answer:
C) H2S
Explanation:
In chemistry, the dissolution of one substance in another is dependent on the magnitude of intermolecular interaction between the two substances. Hence, if two substances do not interact in one way or the other, then one can not dissolve the other.
Let us consider the fact that NH3 is a polar molecule and it is a general principle that like dissolves like. Hence, only H2S which is also a polar molecule can effectively interact with NH3 due to dipole-dipole interaction between the two molecules.
Also, ammonia reacts with hydrogen sulphide as follows;
2NH3 + H2S → (NH4)2S
Hence H2S is more likely to dissolve in NH3.
