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Answer:
-384.22N
Explanation:
From Coulomb's law;
F= Kq1q2/r^2
Where;
K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2
q1 and q2 = magnitudes of the both charges
r= distance of separation
F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2
F= -495.65 × 10^-3/ 1.29 × 10^-3
F= -384.22N
Gamma rays have the highest energies and the shortest wavelengths.
Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is . As the capacitance of capacitor is given as follows.
C =
It is known that the dielectric strength of air is as follows.
E =
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
=
=
=
=
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.