All categories

2 years ago

Simplify 5log z + 5log x + 10 logy.

Mathematics

2 answers:

mafiozo [28]2 years ago

7 0

Step-by-step explanation:

$5 \: log \: z + 5 \: log \: x + 10\: log \: y \\ \\ = log \: {z}^{5} + log \: {x}^{5} + log \: {y}^{10} \\ \\ = log( {z}^{5} \times {x}^{5} \times {y}^{10} ) \\ \\ = log( {x}^{5} {y}^{10} {z}^{5} )$

TEA [102]2 years ago

7 0

Answer:

Step-by-step explanation:

5log z + 5log x + 10 logy= log(z^5) +log(x^5)+log(y^10)

= log(x^5×z^5×y^10)

You might be interested in

The sum of 5 times a number and 6 is twice that number.

nadya68 [22]

Answer:

the number is three

Step-by-step explanation:

6÷2 is equal to 3, so you do 3x5 which is equal to 15.

8 0

2 years ago

If y=3x and 2x−4y=3 , then x=

tatiyna

Answer:

x = -3/10

Step-by-step explanation:

Solve for x by substituting y = 3x into the other equation:

2x - 4y = 3

2x - 4(3x) = 3

Simplify and solve for x:

2x - 12x = 3

-10x = 3

x = -3/10

So, x = -3/10

3 0

2 years ago

Read 2 more answers

A rectangle has a perimeter of 48 ft. The length and width are scaled by a factor 1.5.

prohojiy [21]

Answer: 75

Step-by-step explanation:

when increased in scale,

both sides are multiplied by the factor which is 1.5.

72 =1.5(2L+2W)

Mark me as brainliest

7 0

2 years ago

C is between B and D <br> BC = 8x +13<br> CD= 12x -73<br> BD =320 <br> find the value of x

pentagon [3]

Answer:

...

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

9 months ago