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2 years ago

10

Compute the permutations and combinations. 6 P 4 15 30 360

2 answers:

3241004551 [841]2 years ago

7 0

The answer is c.
6 P 4 = 360

ycow [4]2 years ago

3 0

Answer:

$\text{The value of }_4^6\txterm{P}\text{ is }360$

Step-by-step explanation:

we have to evaluate the permutation

$_4^6\txterm{P}$

The permutation formula can be written as

$_r^n\txterm{P}=\frac{n!}{(n-r)!}$

$_4^6\txterm{P}=\frac{6!}{(6-4)!}=\frac{6!}{2!}$

$=\frac{6\times 5\times 4\times 3\times 2!}{2!}=360$

$\text{Hence, the value of }_4^6\txterm{P}\text{ is }360$

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2 years ago

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1 year ago

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Step-by-step explanation:

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2 years ago

Twice the length of a rectangle is three times the width. The perimeter of the rectangle is 320 cm. Find the dimensions of the r

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2 years ago

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koban [17]

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so that we expect a contribution of

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By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

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5 0

2 years ago