You pick a card at random. Without putting the first card back, you pick a second card at random. 1 2 3 4 5 6 7 8 What is the pr
obability of picking a 1 and then picking an odd number? Write your answer as a percentage rounded to the nearest tenth.
1 answer:
Answer:
%12.8 for the card withe the number 1
%37.8 for the odd number
Step-by-step explanation:
you only have a number one card so thats 1/8 and when converted to percentage is %12.8
theres 3 odd numbers not counting the 1 so thats 3/8 coverted to percent is %37.8
to find percentage to multiply the Numerator by Denominator and multiply by 100
Feel free to ask for more help :)
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Answer:
13 units
Step-by-step explanation:
=
=
=
=13 units
The equation in standard form would be,
All you have to do is move -2/7x to the other side.
Hope this helped
:D
The answer is 7 R 4! hoped this helps!
7x+4<46
7x+4(-4)<46(-4) <- Subtraction Property of Equality
7x<42
7x(/7)<42(/7) <- Division Property of Equality
x<6
I hope this helps!
~kaikers
-182=2(1+2x)-2
2*1=2
2*2x=4x
-182=4x+2-2
-182=4x
-45.5=x
