Answer:
The hypotenuse is 5
Step-by-step explanation:
We can use the Pythagorean theorem to find the hypotenuse of a right triangle
a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse
3^2 +4^2 =c^2
9+16=c^2
25=c^2
Take the square root of each side
sqrt(25) =sqrt(c^2)
5 = c
Answer:
I don't see the file with it
Step-by-step explanation:
30xy + 36x^2 + 30x + 25y
= 6x(5y + 6x) + 5(6x + 5y)
= (6x + 5)(6x + 5y) Answer
Answer:
Step-by-step explanation:
Assuming the maximum score for the final is , we can multiply each score by its respective course weight and add them together to give a final score. If your friend did receive this maximum score of , their overall grade for the course would be:
.
To find the minimum score they need to earn a 75% for the course, we set up the following equation:
, where is the minimum score she needs.
Solving, we get:
.
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>
Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases
Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0 and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>
which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write
where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0 and g2 = 9.8
We get h1 = 3.67m which is the required height