Ask question

Ask question

All categories

2 years ago

14

Questions 4 and 5 refer to the following:

1 answer:

Damm [24]2 years ago

7 0

Answer:

Step-by-step explanation:

Parallel lines are lines that never meet, from the question in the attachment above, the two lines that cannot meet are lines 'a' and 'b' and lines 'c' and 'd'

4. Question four is then lines b and a which is option B

Perpendicular lines are lines in which the angle between them is right angle (90 degrees). Which are 'a' and 'c', 'a' and 'd', 'b' and 'c', 'b' and 'd'

5. Question 5 is therefore 'a' and 'c' which is option D

You might be interested in

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

2 years ago

What do diffraction and refraction have

nignag [31]

Answer:

They are both due to the wave nature of light.

4 0

2 years ago

What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7

Nat2105 [25]

Consider the given equations:

The first equation is as:

$\frac{5}{7} \div \frac{1}{3} = ?$

So, $\frac{5}{7} \div \frac{1}{3}$

= $\frac{5}{7} \times \frac{3}{1}$

Multiplying the given fractions, we get as

= $\frac{15}{7}$

Now, consider the second equation as:

$? \times \frac{1}{3} = \frac{5}{7}$

Multiplying by '3' to both the sides of the equation, we get

$? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}$

$? = \frac{15}{7}$

So, the number which best completes both the equations is $\frac{15}{7}$ .

6 0

2 years ago

This is crazy stuff to me trying to help my child

puteri [66]

I think it is hexagon. It says which polygon at the bottom, and hexagons have six sides like the figure above.

8 0

2 years ago

An angelfish can grow to be 12 inches long. If an angelfish is 8.5 inches longer than a

stepan [7]

A Clown fish would be 3.5 inches

8 0

2 years ago

Read 2 more answers