The motorbike reaches 100 km/h in 3.5 seconds
Explanation:
The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the motorbike in this problem,
u = 0 (it starts from rest)
is the final velocity
is the acceleration
Solving for t, we find the time it takes for the bike to reach that velocity:
Learn more about accelerated motion:
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On the change in potential energy
2.7549 x 10^4 is the answer I hope this helped u
Answer
given,
y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]
length of the rope = 1.33 m
mass of the rope = 3.31 g
comparing the given equation from the general wave equation
y(x,t)= A cos[k x+ω t]
A is amplitude
now on comparing
a) Amplitude = 2.20 mm
b) frequency =
f = 118.25 Hz
c) wavelength
d) speed
v = 105.84 m/s
e) direction of the motion will be in negative x-direction
f) tension
T = 27.87 N
g) Power transmitted by the wave
P = 0.438 W
Answer:
20 V
Explanation:
Power is 100 J/s or 100 W.
We know that P = IV = .
Isolate the potential difference. V = = = 20 V