Answer:
y=4/3
Step-by-step explanation:
Answer:
- 5 min: 3,029,058
- 10 min: 3,398,220
- 60 min: 10,732,234
Step-by-step explanation:
The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).
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<h3>5 minutes</h3>
The number of bacteria present after 5 minutes is about ...
f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058
<h3>10 minutes</h3>
The number of bacteria present after 10 minutes is about ...
f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220
<h3>60 minutes</h3>
The number of bacteria present after 60 minutes is about ...
f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234
Answer:
Step-by-step explanation:
%change=100(final-initial)/(initial)
%change=100(26-20)/20
%change=30%
Since this is positive the number of dogs increased by 30%
The answer to the problem is as follows:
x = sin(t/2)
<span>y = cos(t/2) </span>
<span>Square both equations and add to eliminate the parameter t: </span>
<span>x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 </span>
<span>The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.</span>
There were 5 of the 15 in the simulation that used a coupon. To find the probability you just divide 5 by 15
P(=>4) = 5/15 = 1/3 - probability of 4 or more