The answer is letter is C. 19.5 Because you divide
Answer:
10m/s,15m/s,20m/s,5m/s
Step-by-step explanation:
Speed = distance / time
a) distance = 100m , time = 10s
Speed = distance / time
Speed = 100m/10s
Speed = 10m/s
b) distance = 300m , time = 20s
Speed = distance / time
Speed = 300m/20s
Speed = 15m/s
c) distance = 700m , time = 35s
Speed = distance / time
Speed = 700m/35s
Speed = 20m/s
d) distance = 1000m , time = 200s
Speed = distance / time
Speed = 1000m/200s
Speed = 5m/s
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Answer:
+7
Step-by-step explanation:
if you go from 28 to 21 you see there is a difference of 7 and sense the number is a smaller number now we know the dolphin went up more towards the surface there for there is a change of positive 7
28-21=7
Answer:
(-8.5,9)
Step-by-step explanation:
((-8+(-9))/2=-8.5
(7+11)/2=9
(-8.5,9)
You must develop a cost function C(x) and then minimize its value.
How much dwill the glass cost? It's $1 per sq ft, and the total area of the glass is 4(xh), where x is the length of one side of the base and h is the height of the tank. The area of the metal bottom is x^2, which we must multiply by $1.50 per sq ft.
This cost function will look like this: C(x) = 4($1/ft^2)xh + ($1.50/ft^2)x^2
but we know that (x^2)h= 6 cu ft, or h = (6 cu ft) / (x^2). Subst. this last result into the C(x) equation, immediately above:
C(x) = 4($1/ft^2)x[6 ft^3 / x^2] + ($1.50/ft^2)x^2
Let's focus on the numerical values and ditch the units of measurement for now:
C(x) = 4x(4/x^2) + 1.50x^2, or
C(x) = 16/x + 1.5x^2
Differentiate this with respect to x:
C '(x) = -16 / x^2 + 3 x
Set this equal to 0 and solve for x: -16/x^2 = -3x, or 16 = 3x^3
Then x^3 = 16/3, and x = 5 1/3 ft. We already have the formula
(x^2)h= 6 cu ft, so if x = 5 1/3, or 16/3, then (16/3)^2 h = 6, or
h = 6 / [16/3]^2.
h = 6 (9/256) = 0.21 ft. While possible, this h = 0.21 ft seems quite unlikely.
Please work through this problem yourself, making sure you understand each step. If questions arise, or if you find an error in my approach, please let me know.
Once again:
1. Write a formula for the total cost of the material used: 4 sides of dimensions xh each, plus 1 bottom, of dimensions x^2. Include the unit prices: $1 per square foot for the sides and $1.50 per square foot for the bottom.
2. Differentiate C(x) with respect to x.
3. Set C '(x) = 0 and solve for the critical value(s).
4. Calculate h from your value for x.
5. Write the dimensions of the tank: bottom: x^2; height: h