Hey mate your answer in attachment
Answer: A
Step-by-step explanation:
First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.
When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.
Answer: The solutions are not viable because the amount of the sale cannot be negative.
Step-by-step explanation:
The solution A = -5 is not viable because A represents the amount of sale in dollars and so cannot be a negative number. The minimum amount that a person can make from sales is $0 so anything less than that is not viable.
For instance, if you are selling shoes for $4 each and make no sales in the day, your sales would be $0. It is not possible that your sales would be -$4.
X in the first equation
because 3x + 6y = 9 can be reduced by dividing by 3, thus, giving u
x + 2y = 3.....x = -2y + 3...which u would sub in for x in the other equation