Answer:
0.32 M
Explanation:
Step 1: Write the balanced reaction at equilibrium
Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)
Step 2: Calculate the concentration of Ag⁺ at equilibrium
We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.
Keq = [Ag⁺]² × [S²⁻]
[Ag⁺] = √{Keq / [S²⁻]}
[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M
The textbook would lose potential energy since its falling from a high height.
Answer:
One electron is the answer if you need work i can show
Answer:
Amount of HCL = 0.00318 L of 3.18 ml
Explanation:
Given:
HCL = 2.5 M
NaOH = 0.53 M
Amount of NaOH = 15 ml = 0.015 L
Find:
Amount of HCL
Computation:
HCL react with NaOH
HCl + NaOH ⇒ NaCl + H₂O
So,
Number of moles = Molarity × volume
Number of moles of NaOH = 0.53 × 0.015
Number of moles of NaOH = 0.00795 moles
So,
Number of moles of HCl needed = 0.00795 mol
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So,
Volume = No. of moles / Molarity
Amount of HCL = 0.00795 / 2.5
Amount of HCL = 0.00318 L of 3.18 ml
Answer:
Mass on the moon is 5.1 kg.
Explanation:
Given mass on earth = 5.1 kg
acceleration due to gravity on moon = 1.6 ms⁻².
The mass on the moon does not change because mass is the quantity of matter in the body regardless of its volume or of any forces acting on it.
Whereas the weight of the object changed.
Weight is the the force exerted on a body which is related to mass and expressed as W = mg.
W = weight of object m = mass of object and g = gravitational force
N stands for newton unit of weight.
Thus mass of the object on moon is same as on earth which is 5.1 kg.