Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
(f-v)/a = t
Step-by-step explanation:
f = v + at
Subtract v from each side
f-v = v-v + at
f-v = at
Divide each side by a
(f-v)/a = at/a
(f-v)/a = t
Hello
1 km = 1000 m
12 km = 12,000 m
Each day, she runs 10 * 400 m = 4000 m
12,000 m / 4000 m = 3
It will take 3 days.
Have a nice day
Jack's rent will increase to $445
