X3 − 6x2 − 7x + 60 = 0

The question is below:

SSSSS [86.1K]

Answer:

Triangles ABE and CDE are congruent by AAS.

Step-by-step explanation:

AB ≅ DC (Opposite sides of a parallelogram are congruent.

m < AEB = m < DEC (Vertical angles).

m < ABE = m < EDC ( Alternate Interior angles).

So triangles ABE and CDE are congruent by AAS.

5 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

8 0

2 years ago

How do you find the length of each leg of an isosceles right triangle whose hypotenuse is 4 cm?

allsm [11]

The length of hypotenuse of an isosceles right triangle with two equal legs each 4 cm is given by Pythagorean theorem as follows.

√42+42.

=√32.

=4√2.

4√2 cm.

6 0

2 years ago

Find the area of the lateral faces of the right triangular prism with altitude of 5 cm and base edges of length 3 cm, 4 cm, and

spayn [35]

We know that
area of lateral faces of the <span>right triangular prism=perimeter of base*height

perimeter of the base=[3+4+5]----> 12 cm
height of the prism=5 cm
so
</span>area of lateral faces of the right triangular prism=12 cm*5 cm---> 60 cm²

the answer is
60 cm²

8 0

2 years ago

HELPPPPPPPPP[PPPPPPPP FASTTTTTTTTTTTTT PLSSS

atroni [7]

Answer:

0.75 or... 3/4 of a cup

Step-by-step explanation:

If helpful please give me brainliest.

6 0

1 year ago

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