Answer:
Step-by-step explanation:
Start by multiplying both sides by 2, this will get rid of the fraction on the left side and will result in the equation
Then, subtract 2m from both sides, which leaves the equation as
Then, subtract 6 from both sides, this results with the equation
Finally, divide both sides by 10, this will result in m=-1
Answer:
Area of Circle 1=>64(pi) units^2
Area of Circle 2=>9(pi) units^2
Step-by-step explanation:
Circumference=2(pi)r
Circle 1: 2(pi)r=16(pi)
Divide by 2(pi) on both sides
r=8 units
Area=(pi)r^2
Area of circle 1=>(pi)*(8^2)
Area of Circle 1=>64(pi) units^2
Circle 2: 2(pi)r=6(pi)
Divide by 2(pi) on both sides
r=3 units
Area=(pi)r^2
Area of circle 2=>(pi)*(3^2)
Area of Circle 2=>9(pi) units^2
Find x and y intercept and plot
set x to zero and find y
set y to zero and find x
tada, 2 points
if x=0, then y=-4
if y=0, then x=-16
we havee the points
(0,-4) and (-16,0)
or
y=-1/4x-4
Ok so the lines with two triangles are parralel to eachother. The lines with one are parallel to eachother.
The angle of 109° and angle of z° equal eachother. Z=109°
Since 109°, 33° and y° form a triangle, the sum of the angles will equal 180. Add 109 and 33 to get 142. Subtract 142 from 180 to get y°=38°.
Since z=109, this means that the triangle is congruent with the other. Since the congruent triangles are in a rhombus, then the angles are flipped. Thus, angle x =33°.
z=109°
y=38°
x=33°
No, bc the lower quartile should be in between the minimum and middle quartile(median) Hoped this helped!