<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- To convert the given equation into standard form.
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the standard form of the line is ,
ax + by + c = 0
So the given equation is ,
y = 2/5x -1/3
y = 6x - 5/15
15y = 6x - 5
6x -15y -5 = 0
<u>Hence</u><u> the</u><u> required</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>6</u><u>x</u><u> </u><u>-15y-5=</u><u>0</u><u>.</u>
Answer:
bro tbh just use like or
Step-by-step explanation:
its not that deep
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola? .
At this point you have three parameters to play with, and from the fact that we can already fix one of them, in particular . At this point I would recommend picking an easy value for one of the two, let's say (or even , it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms:
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2:
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need , and at that point the first condition is guaranteed; using the second to find k we get
Or how about a sine wave that oscillates around 2? with a similar reasoning you get
Sky is the limit.
Answer:
Given an angle formed by two lines with a common vertex, this page shows how to ... The above animation is available as a printable step-by-step instruction sheet, which can be ... This construction works by creating two congruent triangles
Step-by-step explanation:
is strictly increasing on [0, 5], so
and
so the integral is bounded between