To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer: 5 and 4
Step-by-step explanation:
Perimeter = 2 ( L + W)
18 = 2(L + W) divide through by 2
9 = L + W
9 - L = W
Area = L * W
20 = L (9 - L)
20 = 9L - L^2
L^2 - 9L + 20 = 0 factor
(L - 5) (L - 4) = 0
Set both factors to 0 and solve for L
L = 5 and L = 4
Answer:
Part A) ΔCGB and ΔPBE are similiar
Part B) They are similar because they are Vertical Angles/Alternate Interior Angles
Part C) Distance from B to E is 125; Distance from P to E is 275.
Step-by-step explanation:
Answer:
6.4
Step-by-step explanation:
16 ÷ 2/5 = 6.4!
that's it
Answer:
8(w - 2)
Step-by-step explanation: