Answer:
x=
Step-by-step explanation:
/2 /2
x=
Answer:
C should be your answer if I'm not right then forgive me please.
Step-by-step explanation:
The speed of the current is 13 mph
<h3>What is speed?</h3>
speed refers to distance travelled per unit time. This is a vector quantity this implies that it has magnitude and direction.
The unit for speed as used here is miles per hour and can be written in short form as mph
<u>Given data</u>
speed of boat = 15 miles per hour = 15 mph
distance = 44 miles upstream
total time for the trip = 7.5 hours
<h3>solving for the speed of the current</h3>
let the water current be x
speed = distance / time
the total travel time upstream and downstream is known
for upstream
15 - x = 44 / time
time = 44 / 15 - x
for downstream
15 + x = 44 / time
time = 44 / 15 + x
total time = time for upstream + time for downstream = 7.5
7.5 = (44 / 15 - x ) + ( 44 / 15 + x )
7.5 = ( 44 ( 15 + x ) + 44 ( 15 - x ) ) / ( 15 + x )( 15 - x )
7.5 ( 15 + x )( 15 - x ) = 210 +44x + 210 - 44x
7.5 ( 225 - x ^ 2 ) = 420
( 225 - x ^ 2 ) = 56
169 = x ^ 2
x = sqrt ( 169 )
x = 13 miles per hour
hence speed of current is 13 miles per hour
Read more on speed here: brainly.com/question/4931057
#SPJ1
Answer: - 7.2 , 2.6 , 12.4 and 22.2
Step-by-step explanation:
Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:
-17 , p , q , r , s , 32
The first term (a ) = -17
Last term (L) = 32
common difference (d) = ?
number of terms (n ) = 6
We will use the formula for calculating the last term to find the common difference. That is
L = a + (n - 1 ) d
Substituting the values , we have
32 = -17 + (6-1) d
32 = -17 + 5d
32 + 17 = 5d
49 = 5d
Therefore: d = 9.8
We can therefore find the values of p , q , r , and s
p is the second term , that is
p = a + d
p = -17 + 9.8
p = -7.2
q = a + 2d
q = - 17 + 19.6
q = 2.6
r = a + 3d
r = - 17 + 29.4
r = 12.4
s = a + 4d
s = - 17 + 39.2
s = 22.2
Therefore : the arithmetic means are : - 7.2 , 2.6 , 12.4 and 22.2
$21 because 3$x$7(numbers of days in a week)is $21. I hope this helps :)
