' W ' is the symbol for 'Watt' ... the unit of power equal to 1 joule/second.
That's all the physics we need to know to answer this question.
The rest is just arithmetic.
(60 joules/sec) · (30 days) · (8 hours/day) · (3600 sec/hour)
= (60 · 30 · 8 · 3600) (joule · day · hour · sec) / (sec · day · hour)
= 51,840,000 joules
__________________________________
Wait a minute ! Hold up ! Hee haw ! Whoa !
Excuse me. That will never do.
I see they want the answer in units of kilowatt-hours (kWh).
In that case, it's
(60 watts) · (30 days) · (8 hours/day) · (1 kW/1,000 watts)
= (60 · 30 · 8 · 1 / 1,000) (watt · day · hour · kW / day · watt)
= 14.4 kW·hour
Rounded to the nearest whole number:
14 kWh
Answer:
PE=0.92414J and KE=0.28175J
Explanation:
Gravitational potential energy=mass*gravity*height
PE=mgh
Data,
M=0.046kg
H=2.05m
g=9.8m/s^2
PE=0.046kg * 9.8m/s^2 * 2.05m
PE =0.92414J
KE=1/2mv^2
M=0.046kg
V=3.5m/s
KE=[(0.046kg)*(3.5m/s)^2]\2
KE=0.28175J
#1
for the block of mass 5 kg normal force is given as
friction force is given as
Net force is given as
now we know that
#2
Normal force is given as
now we know that
as object moves with constant velocity
now for coefficient of friction we can use
#3
net force upwards is given as
mass is given as
now as per newton's law we can say
#4
As we know that when block is sliding on rough surface
part a)
net force = applied force - frictional force
part b)
for coefficient of friction we can use
here normal force is given as
now we have
#5
if an object is initially at rest and moves 20 m in 5 s
so we can use kinematics to find out the acceleration
now net force is given as
#6
an object travelling with speed 25 m/s comes to stop in 1.5 s
so here acceleration of object is given as
now the force is gievn as