Answer : Given data ;
Δ G° = 212 KJ/molTemperature is = 25+273 = 298 KAnd gas constant R = 0.008314 KJ/mol
The reaction is NiO(s) ⇌ Ni(s) +
We can find out the pressure on oxygen by using the equation of gibb's free energy with remainder quotient which is, ΔG = ΔG° +RT lnQ
when at equilibrium Q = K, here K is equilibrim constant, and ΔG becomes 0;
so we get, 0 = ΔG° + RT ln K
on rearranging we get, ln K = ΔG° / (RT)
ln K = 212 / (0.00831 X 298) = 85.6
Here, now K = = 1.51 X
When we get K = 1.51 X
But, K =
So, (1.51 X
)
= 3.87 X
Hence, the
pressure of oxygen will be = 3.87 X Pa
Now, Pa to atm conversion will be 3.756 X atm
Answer:
The answer to your question is 245.9 g of Fe₂O₃
Explanation:
Data
grams of Fe₂O₃ = ?
grams of Fe = 172 g
Balanced chemical reaction
Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O
Process
1.- Calculate the molar mass of of Iron Oxide and Iron
Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g
2Fe = 2 x 56 = 112 g
2.- Use proportions and cross multiplication to solve this problem
160 g of Fe₂O₃ --------------- 112 g of Fe
x ---------------- 172 g of Fe
x = (172 x 160)/112
x = 27520/112
x = 245.9 g of Fe₂O₃
There was no equipment to create temperature difference in the water
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Explanation:
Energy transferred per second in given area:
8000 x 3.9 / 10000
Energy transferred = 3.12 J
Using Planck's equation:
E = nhc/λ
n = (3.12 x 510 x 10⁻⁹) / (3 x 10⁸ x 6.63 x 10⁻³⁴)
n = 8 x 10¹⁸ photons