The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.
<h3>How to calculate probability?</h3>
From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.
Therefore, the probability of getting a blue M&M will be:
= 132/1023
= 0.1290
Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:
= 0.1290 × 5
= 0.6450
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First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
I don’t feel like doing school and I keep getting distracted by this app
Answer: x = 9/11
Step-by-step explanation:
First, distribute 9 to x and -1
9x - 9 = 2
Then add 9 to both sides
9x = 11
Then divide both sides by 9
x = 9/11
Hope it helps :)
Answer:
39 men, 13 women
Step-by-step explanation:
you're saying you just need the answer so i hope this works. good luck :)