Answer:
The percent of the area under the density curve where is more that 3 is 25 %.
Step-by-step explanation:
Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:
(1)
Where:
- Area, in square units.
- Base of the triangle, in units.
- Height of the triangle, in units.
The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:
The percent of the area under the density curve where is more that 3 is 25 %.
Correct answer is: F(x)=-x^2-3
Step-by-step explanation:
We are given a function:
The graph of is also shown in the given question figure.
It is a parabola with vertex at (0,0).
Sign of is positive, that is why the parabola opens up.
General equation of parabola is given as:
Here, in G(x), a = 1
Vertex (h,k) is (0,0).
As seen from the question figure,
The graph of F(x) opens down that is why it will have:
Sign of as negative. i.e.
And vertex is at (0,-3)
Putting the values of a and vertex coordinates,
Hence, the equation of parabola will become:
The answer is 1.
8x6=48
8x5 + 8x1 = 48
I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:
In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]