Answer:
D. 1 BB : 2 Bb : 1 bb
Explanation:
This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.
If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:
Bb = B and b
Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:
1 BB : 2 Bb : 1 bb
BB and Bb = black fur guinea pigs
bb = white fur guinea pigs
Answer:
A.
Explanation:
When we say that an individual is <u>heterozygous</u>, it means that the two alleles at the locus we are studying are different from one another. That is, each one of the parents contributed a different allele.
On the other hand, If the alleles at that locus were the same we would say the individual is <u>homozygous</u>. In other words, the two parents contributed each the same type of allele.
Answer:
I'm pretty sure it's transport blood cells
Answer:
The vascular tissues, they are called the xylem and phloem.