The prime factors of 6 are 2 and 3. So for a number to be divisible by 6,it must also be divisible by 2 and 3.Therefore,we need to check if a number is even and then check if the sum of the digits is divisible by 3
I think it's D. 7 times out of 34 times
Answer:
Step-by-step explanation:
let 7 + 3√2 be an rational number where
7+3√2 = a/b [ a and b are coprime and b is not equal to zero]
3√2= a/b-7
3√2 =( a-7b) /b
√2 = (a-7b) /3b .....(i)
Now ,from equation (i) ,we get that √2 is rational but we know that √2 is irrational. so actually 7 + 3√2 is irrational not rational. thus our assumption is wrong. The number is irrational.
