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2 years ago

Which of the following sets of numbers could be the lengths of the sides of a triangle?

1 answer:

7 0

B. 3ft, 4ft, 5ft

Pythagoras' Theorem where the square of the two smaller sides added together equals the square of the hypotenuse. If the two smaller sides are 3 and 4 then the hypotenuse is always going to be 5

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Does anyone understand and can help me asap?

nydimaria [60]

Answer:

see below

Step-by-step explanation:

Circumference of circle = 2πr =dπ

Area of circle =πr²

1) Circle1 d =4 in, r =2 in

Circumference of circle1 =4π in

Area of circle1 = 2²π =4π in²

2) Circle2: d =3 in, r =1.5 in

Circumference of circle2 =3π in

Area of circle2 = 1.5²π =2.25π in²

3) Circle3: r =1 in, d =2 in

Circumference of circle3 =2π in

Area of circle3 = 1²π =π in²

4) Circle4: r =2 1/2 in = 2.5 in, d =5 in

Circumference of circle4 =5π in

Area of circle4 = 2.5²π = 6.25π in²

5) 2/3 of the Area of circle1 = (2/3)*4π in²= (8/3)π in²

6) 1/2 of the Area of circle2 = (1/2)*2.25π in² = (1/2)*(9/4)π in² = (9/8)π in²

7) 1/4 of the Area of circle3 = (1/4)π in²

8) 1/3 of the Area of circle4 = (1/3)* 6.25π in² =(1/3)*(25/4)π in² = (25/12)π in²

6 0

2 years ago

Find the volume of rectangular prism if the length is 4X +3 with is X -6 and a height is 2X -1

cricket20 [7]

Answer: 8x³ - 46x² - 15x + 18

Step-by-step explanation:

To find the volume of a rectangular prism we will multiply each of the three dimensions given

First, let's multiply 4x+3 by x-6: (4x+3)(x-6) = 4x² - 21x - 18

Then we will multiply 4x²... by 2x-1: (4x²-21x-18)(2x-1) = 8x³ - 46x² - 15x + 18

5 0

2 years ago

Consider the following equation f(x)=(x^2+4)/(4x^2-4x-8)

kifflom [539]

Question:

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

Answer:

The vertical asymptotes are x = 2 or x = -1

Solution:

Given that,

$f(x)=\frac{x^2+4}{4x^2-4x-8}$

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation

$4x^2-4x-8=0\\\\Divide\ by\ 2\\\\x^2 - 2x - 4 = 0$

$Split\ the\ middle\ term\\\\x^2+x-2x-2=0\\\\Group\ the\ equation\\\\(x^2 + x) - (2x + 2) = 0\\\\Factor\ the\ common\ term\\\\x(x + 1) - 2(x + 1) = 0\\\\(x + 1)(x - 2) = 0\\\\Therefore,\\\\x + 1 = 0\\\\x = -1\\\\And\\\\x - 2 = 0\\\\x = 2$

Thus the vertical asymptotes are x = - 1 and x = 2

3 0

2 years ago

Read 2 more answers

The least-squares regression equation

Contact [7]

Answer:

✔ 0.4

✔ 0.4 centimeters less

✔ 9.2

1.16(5) + 3 = 8.8

9.2 - 8.8 = .4

ED2021

3 0

2 years ago

Help Please 20 POINTS Which expressions are equivalent to the following?

o-na [289]

Answer:

$\large\boxed{5x(6x-x-2)}\\\\\boxed{-5(-6x^2+x+2)}\\\\\boxed{5(2x+1)(3x-2)}$

Step-by-step explanation:

$30x^2-5x-10=5(6x^2-x-2)=5(-1)(-6x^2+x+2)=-5(-6x^2+x+2)\\\\30x^2-5x-10=30x^2+15x-20x-10=15x(2x+1)-10(2x+1)\\\\=(2x+1)(15x-10)=(2x+1)(5)(3x-2)=5(2x-1)(3x-2)$

4 0

2 years ago