Answer:
Hydochloric acid
HCl
Explanation:
Hydrochloric acid is an acid and ionizes to form hydrogen and chloride ions.
The name of the compound that gives hydrogen ion and chloride ions in the solution state is Hydrochloric acid.
Hydrochloric acid is made up of one atom of hydrogen and 1 atom of chlorine. We can also say, it is made up of 1 mole of hydrogen and 1 mole of chlorine.
The formula of this compound is HCl;
In solution:
HCl
→ H⁺ + Cl⁻
Answer;
B. They are large molecules that increase the rate of biologically important reactions.
Explanation;
-Enzymes are biological molecules, that are protein in nature, that significantly speed up the rate of virtually all of the chemical reactions that take place within cells.
-They are vital for life and serve a wide range of important functions in the body, such as aiding in digestion and metabolism. Some enzymes help break large molecules into smaller pieces that are more easily absorbed by the body. Other enzymes help bind two molecules together to produce a new molecule.
Rift Valley Examples
- East African
- Rhine Rift Valley (Germany)
- Baikal Rift Valley (Russia)
Rift Valley Facts/Characteristics
- Bordered by fault zones and separating land masses
- A portion of land that drops, forming a valley.
- Formed as tectonic plates move.
Fossils - Examples
- Bones
- Shells
- Exoskeletons
- Stone imprints of animals.
Non Examples of Fossils
- Stones
- rocks
- Some bones (If they are fossils they will be a lot heavier than other bones.
Hope this helps.
The balanced chemical reaction is written as:
<span>CH4 (g) + 2 O2 (g) ----> CO2 (g) + 2 H2O (g)
</span>
We are given the amount of water to be produced from the reaction. This amount will be used for the calculations. Calculations are as follows:
12.4 L H2O ( 1 mol / 22.4 L ) ( 1 mol CH4 / 2 mol H2O ) ( 22.4 L / 1 mol ) = 6.2 L CH4
Answer:
c.boron-11
Explanation:
The atomic mass of boron is 10.81 u.
And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.
To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:
(10u)(x)+(11u)(1−x)100%=10.81u
Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.
Solving for x we get:
11u−ux=10.81u
0.19u=ux
x=0.19
1−x=0.81
And thus the abundance of boron-11 is roughly 81%.
